Maths Chapter 12: Surface Areas and Volumes
Class 10 Maths NCERTIn this chapter, you will study how to determine the surface area of an object formed by combining any two of the basic solids - cuboid, cone, cylinder, sphere and hemisphere.
Also, how to find the volume of objects formed by combining any two of a cuboid, cone, cylinder, sphere and hemisphere.
Given a right circular cone, which is sliced through by a plane parallel to its base, when the smaller conical portion is removed, the resulting solid is called a Frustum of a Right Circular Cone. The formulae involving the frustum of a cone are:
Volume of a frustum of a cone = 1/3 × πh × (r12 + r22 + r1r2)
Curved surface area of a frustum of a cone = πl(r1 + r2)
Total surface area of frustum of a cone = πl(r1 + r2) + π(r12 + r22)