A 0.108 mol of sample gas has a volume of 0.505 L at 20°C. What is the pressure exerted by it?
A
:
5.99 atm
B
:
5.14 atm
C
:
6 atm
D
:
7 atm
General Science
Physics
Laws and Principles
Answer
Option 2 : 5.14 atm
Explanation
Given,
n= 0.108 mol
V= 0.505 L
T= 20 + 273= 293 K
R= 0.08206 L-atm/mol-K
To find P
According to the Ideal Gas Law,
PV= nRT
or, P= \(\frac{nRT}{V}\)
= \(\frac{0.108×0.08206×293}{0.505}\)
= 5.14 atm