Calculate the work done to take an object of mass 10 kg to a height of 20 m. (g = 9.8 m/s2).
A
:
98 J
B
:
980 J
C
:
-1960 J
D
:
19.6 J
General Science
Physics
Work Power Energy
Answer
Option 3 : -1960 J
Explanation
Given data: m = 10 kg; s = 20 m; g = 9.8 m/s2 F = m.g = 10 × (-9.8) (The negative sign is taken because the displacement is opposite to the direction of the force.) F = -98 N W = F × s = -98 × 20 W = -1960 J (The negative sign appears because the direction of the force is opposite to the direction of displacement so that the work done is negative.)
Note: When work is done against gravity it is taken as negative and when gravity does work for us it is taken positively.
http://www.ncert.nic.in/ncerts/l/iesc111.pdf